4(x-4)^2/-38-(y-3)^2/-38=1

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Solution for 4(x-4)^2/-38-(y-3)^2/-38=1 equation: 


x in (-oo:+oo)

t_1 = -(((y-3)^2)/(-38))-1

(4*(x-4)^2)/(-38)+t_1 = 0

(4*(x-4)^2)/(-38)+(-38*t_1)/(-38) = 0

4*(x-4)^2-38*t_1 = 0

4*x^2-38*t_1-32*x+64 = 0

(4*x^2-38*t_1-32*x+64)/(-38) = 0

(4*x^2-38*t_1-32*x+64)/(-38) = 0 // * -38

4*x^2-38*t_1-32*x+64 = 0

4*x^2-38*t_1-32*x+64 = 0

DELTA = (-32)^2-(4*4*(64-38*t_1))

DELTA = 1024-16*(64-38*t_1)

1024-16*(64-38*t_1) = 0

1024-16*(64-38*t_1) = 0

608*t_1 = 0

608*t_1 = 0

608*t_1 = 0 // : 608

t_1 = 0

DELTA = 0  <=>  t_4 = 0

x = 32/(2*4) i t_1 = 0

x = 4 i t_1 = 0

( x = ((1024-16*(64-38*t_1))^(1/2)+32)/(2*4) or x = (32-(1024-16*(64-38*t_1))^(1/2))/(2*4) ) i t_1 > 0

( x = ((1024-16*(64-38*t_1))^(1/2)+32)/8 or x = (32-(1024-16*(64-38*t_1))^(1/2))/8 ) i t_1 > 0

t_1+0 > 0

t_1 > 0

t_1+0 > 0 // - 0

t_1 > 0

x in { 4, ((1024-16*(64-38*(-(((y-3)^2)/(-38))-1)))^(1/2)+32)/8, (32-(1024-16*(64-38*(-(((y-3)^2)/(-38))-1)))^(1/2))/8 }

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